13424442403 has 4 divisors (see below), whose sum is σ = 13887354240. Its totient is φ = 12961530568.

The previous prime is 13424442373. The next prime is 13424442433. The reversal of 13424442403 is 30424442431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30424442431 = 167159 ⋅182009.

It is an interprime number because it is at equal distance from previous prime (13424442373) and next prime (13424442433).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13424442403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13424442433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231455875 + ... + 231455932.

It is an arithmetic number, because the mean of its divisors is an integer number (3471838560).

Almost surely, 2^13424442403 is an apocalyptic number.

13424442403 is a deficient number, since it is larger than the sum of its proper divisors (462911837).

13424442403 is an equidigital number, since it uses as much as digits as its factorization.

13424442403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 462911836.

The product of its (nonzero) digits is 36864, while the sum is 31.

Adding to 13424442403 its reverse (30424442431), we get a palindrome (43848884834).

The spelling of 13424442403 in words is "thirteen billion, four hundred twenty-four million, four hundred forty-two thousand, four hundred three".