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1342462522561 = 3114316599751
BaseRepresentation
bin10011100010010001000…
…000000111010011000001
311202100010112002002121221
4103202101000013103001
5133443330401210221
62504415130515041
7165663321110266
oct23422100072301
94670115062557
101342462522561
11478376106946
12198217b95a81
13997943b6834
1448d92c0d26d
1524dc1bd3541
hex138910074c1

1342462522561 has 4 divisors (see below), whose sum is σ = 1346779122624. Its totient is φ = 1338145922500.

The previous prime is 1342462522559. The next prime is 1342462522601. The reversal of 1342462522561 is 1652252642431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342462522561 - 21 = 1342462522559 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342462522361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2158299565 + ... + 2158300186.

It is an arithmetic number, because the mean of its divisors is an integer number (336694780656).

Almost surely, 21342462522561 is an apocalyptic number.

It is an amenable number.

1342462522561 is a deficient number, since it is larger than the sum of its proper divisors (4316600063).

1342462522561 is an equidigital number, since it uses as much as digits as its factorization.

1342462522561 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4316600062.

The product of its digits is 691200, while the sum is 43.

The spelling of 1342462522561 in words is "one trillion, three hundred forty-two billion, four hundred sixty-two million, five hundred twenty-two thousand, five hundred sixty-one".

Divisors: 1 311 4316599751 1342462522561