Base | Representation |
---|---|
bin | 1100001101011101010100… |
… | …1110110111000011100011 |
3 | 1202112110011202000122111211 |
4 | 3003113111032313003203 |
5 | 3224430104130230111 |
6 | 44315304252250551 |
7 | 2553643460121133 |
oct | 303272516670343 |
9 | 52473152018454 |
10 | 13425350242531 |
11 | 4306728239557 |
12 | 1609b0a770a57 |
13 | 76500b26c666 |
14 | 345b0cca2ac3 |
15 | 184356888521 |
hex | c35d53b70e3 |
13425350242531 has 4 divisors (see below), whose sum is σ = 13752797809464. Its totient is φ = 13097902675600.
The previous prime is 13425350242429. The next prime is 13425350242537. The reversal of 13425350242531 is 13524205352431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13425350242531 - 29 = 13425350242019 is a prime.
It is a super-2 number, since 2×134253502425312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13425350242537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163723783405 + ... + 163723783486.
It is an arithmetic number, because the mean of its divisors is an integer number (3438199452366).
Almost surely, 213425350242531 is an apocalyptic number.
13425350242531 is a deficient number, since it is larger than the sum of its proper divisors (327447566933).
13425350242531 is an equidigital number, since it uses as much as digits as its factorization.
13425350242531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327447566932.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 13425350242531 its reverse (13524205352431), we get a palindrome (26949555594962).
The spelling of 13425350242531 in words is "thirteen trillion, four hundred twenty-five billion, three hundred fifty million, two hundred forty-two thousand, five hundred thirty-one".
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