Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …0101111100011000010011 |
3 | 1202112110100211200120010212 |
4 | 3003113121211330120103 |
5 | 3224430231342340030 |
6 | 44315315424314335 |
7 | 2553645336015425 |
oct | 303273145743023 |
9 | 52473324616125 |
10 | 13425423402515 |
11 | 4306765568753 |
12 | 1609b2b1729ab |
13 | 7650204765a7 |
14 | 345b188a8815 |
15 | 18435ceda595 |
hex | c35d997c613 |
13425423402515 has 4 divisors (see below), whose sum is σ = 16110508083024. Its totient is φ = 10740338722008.
The previous prime is 13425423402497. The next prime is 13425423402527. The reversal of 13425423402515 is 51520432452431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13425423402515 - 26 = 13425423402451 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342542340247 + ... + 1342542340256.
It is an arithmetic number, because the mean of its divisors is an integer number (4027627020756).
Almost surely, 213425423402515 is an apocalyptic number.
13425423402515 is a deficient number, since it is larger than the sum of its proper divisors (2685084680509).
13425423402515 is an equidigital number, since it uses as much as digits as its factorization.
13425423402515 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2685084680508.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 13425423402515 its reverse (51520432452431), we get a palindrome (64945855854946).
The spelling of 13425423402515 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-three million, four hundred two thousand, five hundred fifteen".
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