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13425430012051 = 61971226662221
BaseRepresentation
bin1100001101011101100111…
…1111001010000010010011
31202112110101022010100201111
43003113121333022002103
53224430240040341201
644315320222114151
72553645446134261
oct303273177120223
952473338110644
1013425430012051
114306769272582
121609b3141b957
1376502194bb65
14345b19709431
1518435d893b51
hexc35d9fca093

13425430012051 has 8 divisors (see below), whose sum is σ = 13659572146608. Its totient is φ = 13191741204000.

The previous prime is 13425430012019. The next prime is 13425430012061. The reversal of 13425430012051 is 15021003452431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13425430012051 - 25 = 13425430012019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13425430012061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 113271880 + ... + 113390341.

It is an arithmetic number, because the mean of its divisors is an integer number (1707446518326).

Almost surely, 213425430012051 is an apocalyptic number.

13425430012051 is a deficient number, since it is larger than the sum of its proper divisors (234142134557).

13425430012051 is an equidigital number, since it uses as much as digits as its factorization.

13425430012051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 226663253.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13425430012051 its reverse (15021003452431), we get a palindrome (28446433464482).

The spelling of 13425430012051 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty million, twelve thousand, fifty-one".

Divisors: 1 61 971 59231 226662221 13826395481 220089016591 13425430012051