1343001013003 has 4 divisors (see below), whose sum is σ = 1446308783248. Its totient is φ = 1239693242760.

The previous prime is 1343001012959. The next prime is 1343001013009. The reversal of 1343001013003 is 3003101003431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1343001013003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343001013009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51653885103 + ... + 51653885128.

It is an arithmetic number, because the mean of its divisors is an integer number (361577195812).

Almost surely, 2^{1343001013003} is an apocalyptic number.

1343001013003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1343001013003 is a deficient number, since it is larger than the sum of its proper divisors (103307770245).

1343001013003 is a wasteful number, since it uses less digits than its factorization.

1343001013003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103307770244.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1343001013003 its reverse (3003101003431), we get a palindrome (4346102016434).

The spelling of 1343001013003 in words is "one trillion, three hundred forty-three billion, one million, thirteen thousand, three".