Base | Representation |
---|---|
bin | 10011100010110001110… |
… | …110100000000101000011 |
3 | 11202101112221010022101021 |
4 | 103202301312200011003 |
5 | 134000442443311010 |
6 | 2504545535250311 |
7 | 166013062451110 |
oct | 23426166400503 |
9 | 4671487108337 |
10 | 1343013650755 |
11 | 478629214697 |
12 | 198350679997 |
13 | 998516306aa |
14 | 490060b3907 |
15 | 24e0529a8da |
hex | 138b1da0143 |
1343013650755 has 16 divisors (see below), whose sum is σ = 1845465877440. Its totient is φ = 919114353792.
The previous prime is 1343013650729. The next prime is 1343013650761. The reversal of 1343013650755 is 5570563103431.
It is a cyclic number.
It is not a de Polignac number, because 1343013650755 - 25 = 1343013650723 is a prime.
It is a super-2 number, since 2×13430136507552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37675524 + ... + 37711153.
It is an arithmetic number, because the mean of its divisors is an integer number (115341617340).
Almost surely, 21343013650755 is an apocalyptic number.
1343013650755 is a deficient number, since it is larger than the sum of its proper divisors (502452226685).
1343013650755 is an equidigital number, since it uses as much as digits as its factorization.
1343013650755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75387198.
The product of its (nonzero) digits is 567000, while the sum is 43.
The spelling of 1343013650755 in words is "one trillion, three hundred forty-three billion, thirteen million, six hundred fifty thousand, seven hundred fifty-five".
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