Base | Representation |
---|---|
bin | 1100001101110000001110… |
… | …1010111110010001011011 |
3 | 1202112221021100211001211112 |
4 | 3003130003222332101123 |
5 | 3230021002112100410 |
6 | 44321503551450535 |
7 | 2554213302142043 |
oct | 303340352762133 |
9 | 52487240731745 |
10 | 13430424331355 |
11 | 43088a144a599 |
12 | 160aaa5b26a4b |
13 | 76563956bb95 |
14 | 346070b2c723 |
15 | 184552077105 |
hex | c3703abe45b |
13430424331355 has 16 divisors (see below), whose sum is σ = 16524783281664. Its totient is φ = 10472638917120.
The previous prime is 13430424331343. The next prime is 13430424331399. The reversal of 13430424331355 is 55313342403431.
It is not a de Polignac number, because 13430424331355 - 214 = 13430424314971 is a prime.
It is a super-2 number, since 2×134304243313552 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29912522 + ... + 30358191.
It is an arithmetic number, because the mean of its divisors is an integer number (1032798955104).
Almost surely, 213430424331355 is an apocalyptic number.
13430424331355 is a deficient number, since it is larger than the sum of its proper divisors (3094358950309).
13430424331355 is a wasteful number, since it uses less digits than its factorization.
13430424331355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60271846.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 13430424331355 its reverse (55313342403431), we get a palindrome (68743766734786).
The spelling of 13430424331355 in words is "thirteen trillion, four hundred thirty billion, four hundred twenty-four million, three hundred thirty-one thousand, three hundred fifty-five".
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