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13431000131 = 24155730291
BaseRepresentation
bin11001000001000110…
…01100110001000011
31021200000210111111022
430200203030301003
5210001314001011
610100424540055
7653555421533
oct144043146103
937600714438
1013431000131
1157724a420a
12272a02162b
131360778573
14915abd4c3
155391da8db
hex3208ccc43

13431000131 has 4 divisors (see below), whose sum is σ = 13486730664. Its totient is φ = 13375269600.

The previous prime is 13431000113. The next prime is 13431000133. The reversal of 13431000131 is 13100013431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13431000131 - 230 = 12357258307 is a prime.

It is a super-2 number, since 2×134310001312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13431000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27864905 + ... + 27865386.

It is an arithmetic number, because the mean of its divisors is an integer number (3371682666).

Almost surely, 213431000131 is an apocalyptic number.

13431000131 is a deficient number, since it is larger than the sum of its proper divisors (55730533).

13431000131 is an equidigital number, since it uses as much as digits as its factorization.

13431000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55730532.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13431000131 its reverse (13100013431), we get a palindrome (26531013562).

The spelling of 13431000131 in words is "thirteen billion, four hundred thirty-one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 241 55730291 13431000131