1343112444433 has 4 divisors (see below), whose sum is σ = 1343254416948. Its totient is φ = 1342970471920.

The previous prime is 1343112444419. The next prime is 1343112444437. The reversal of 1343112444433 is 3344442113431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1036338252049 + 306774192384 = 1018007^2 + 553872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1343112444433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343112444392 and 1343112444401.

It is not an unprimeable number, because it can be changed into a prime (1343112444437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70972066 + ... + 70990987.

It is an arithmetic number, because the mean of its divisors is an integer number (335813604237).

Almost surely, 2^{1343112444433} is an apocalyptic number.

It is an amenable number.

1343112444433 is a deficient number, since it is larger than the sum of its proper divisors (141972515).

1343112444433 is an equidigital number, since it uses as much as digits as its factorization.

1343112444433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141972514.

The product of its digits is 165888, while the sum is 37.

Adding to 1343112444433 its reverse (3344442113431), we get a palindrome (4687554557864).

The spelling of 1343112444433 in words is "one trillion, three hundred forty-three billion, one hundred twelve million, four hundred forty-four thousand, four hundred thirty-three".