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13431425040051 = 39331947976743
BaseRepresentation
bin1100001101110011111101…
…0100010111111010110011
31202120000212002211100002120
43003130333110113322303
53230030024302240201
644322151140245323
72554250143054104
oct303347724277263
952500762740076
1013431425040051
114309265307877
12160b1250a0843
137657689967c5
143461279c23ab
151845aed48536
hexc373f517eb3

13431425040051 has 8 divisors (see below), whose sum is σ = 17908759000320. Its totient is φ = 8954187219912.

The previous prime is 13431425040031. The next prime is 13431425040073. The reversal of 13431425040051 is 15004052413431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13431425040051 - 213 = 13431425031859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13431425039994 and 13431425040021.

It is not an unprimeable number, because it can be changed into a prime (13431425040031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23708415 + ... + 24268328.

It is an arithmetic number, because the mean of its divisors is an integer number (2238594875040).

Almost surely, 213431425040051 is an apocalyptic number.

13431425040051 is a deficient number, since it is larger than the sum of its proper divisors (4477333960269).

13431425040051 is an equidigital number, since it uses as much as digits as its factorization.

13431425040051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48070065.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13431425040051 its reverse (15004052413431), we get a palindrome (28435477453482).

The spelling of 13431425040051 in words is "thirteen trillion, four hundred thirty-one billion, four hundred twenty-five million, forty thousand, fifty-one".

Divisors: 1 3 93319 279957 47976743 143930229 4477141680017 13431425040051