Base | Representation |
---|---|
bin | 11001000001010000… |
… | …01101100100100001 |
3 | 1021200010021020222111 |
4 | 30200220031210201 |
5 | 210002133023040 |
6 | 10100513035321 |
7 | 653602533505 |
oct | 144050154441 |
9 | 37603236874 |
10 | 13432314145 |
11 | 5773211478 |
12 | 272a555b41 |
13 | 1360b186a3 |
14 | 915d42305 |
15 | 539399dea |
hex | 320a0d921 |
13432314145 has 4 divisors (see below), whose sum is σ = 16118776980. Its totient is φ = 10745851312.
The previous prime is 13432314143. The next prime is 13432314187. The reversal of 13432314145 is 54141323431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7531462656 + 5900851489 = 86784^2 + 76817^2 .
It is a cyclic number.
It is not a de Polignac number, because 13432314145 - 21 = 13432314143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13432314143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343231410 + ... + 1343231419.
It is an arithmetic number, because the mean of its divisors is an integer number (4029694245).
Almost surely, 213432314145 is an apocalyptic number.
It is an amenable number.
13432314145 is a deficient number, since it is larger than the sum of its proper divisors (2686462835).
13432314145 is an equidigital number, since it uses as much as digits as its factorization.
13432314145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2686462834.
The product of its digits is 17280, while the sum is 31.
Adding to 13432314145 its reverse (54141323431), we get a palindrome (67573637576).
The spelling of 13432314145 in words is "thirteen billion, four hundred thirty-two million, three hundred fourteen thousand, one hundred forty-five".
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