Base | Representation |
---|---|
bin | 1100001101110111100110… |
… | …0101010001110100010001 |
3 | 1202120010101020011222200222 |
4 | 3003131321211101310101 |
5 | 3230034030023100113 |
6 | 44322432135522425 |
7 | 2554313312545325 |
oct | 303357145216421 |
9 | 52503336158628 |
10 | 13432402550033 |
11 | 430971706a565 |
12 | 160b358529415 |
13 | 76589335b08c |
14 | 3461bb757985 |
15 | 18461aa85e08 |
hex | c3779951d11 |
13432402550033 has 8 divisors (see below), whose sum is σ = 13438902131616. Its totient is φ = 13425904548000.
The previous prime is 13432402549999. The next prime is 13432402550069. The reversal of 13432402550033 is 33005520423431.
13432402550033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13432402550033 - 28 = 13432402549777 is a prime.
It is a super-2 number, since 2×134324025500332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13432402549975 and 13432402550002.
It is not an unprimeable number, because it can be changed into a prime (13432402559033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16797653 + ... + 17579133.
It is an arithmetic number, because the mean of its divisors is an integer number (1679862766452).
Almost surely, 213432402550033 is an apocalyptic number.
It is an amenable number.
13432402550033 is a deficient number, since it is larger than the sum of its proper divisors (6499581583).
13432402550033 is an equidigital number, since it uses as much as digits as its factorization.
13432402550033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 789775.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 13432402550033 its reverse (33005520423431), we get a palindrome (46437922973464).
The spelling of 13432402550033 in words is "thirteen trillion, four hundred thirty-two billion, four hundred two million, five hundred fifty thousand, thirty-three".
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