Base | Representation |
---|---|
bin | 11110100010101101001111… |
… | …111001100001100111001001 |
3 | 122121121111000202011102221201 |
4 | 132202231033321201213021 |
5 | 120101301023310143340 |
6 | 1153404414343104201 |
7 | 40202523320441263 |
oct | 3642551771414711 |
9 | 577544022142851 |
10 | 134326442662345 |
11 | 39889584aaa74a |
12 | 13095445a42061 |
13 | 59c4c10580a8b |
14 | 2525612442b33 |
15 | 107e2143a579a |
hex | 7a2b4fe619c9 |
134326442662345 has 4 divisors (see below), whose sum is σ = 161191731194820. Its totient is φ = 107461154129872.
The previous prime is 134326442662229. The next prime is 134326442662361. The reversal of 134326442662345 is 543266244623431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19128123292041 + 115198319370304 = 4373571^2 + 10733048^2 .
It is a cyclic number.
It is not a de Polignac number, because 134326442662345 - 237 = 134189003708873 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13432644266230 + ... + 13432644266239.
It is an arithmetic number, because the mean of its divisors is an integer number (40297932798705).
Almost surely, 2134326442662345 is an apocalyptic number.
It is an amenable number.
134326442662345 is a deficient number, since it is larger than the sum of its proper divisors (26865288532475).
134326442662345 is an equidigital number, since it uses as much as digits as its factorization.
134326442662345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26865288532474.
The product of its digits is 59719680, while the sum is 55.
The spelling of 134326442662345 in words is "one hundred thirty-four trillion, three hundred twenty-six billion, four hundred forty-two million, six hundred sixty-two thousand, three hundred forty-five".
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