1343311413131 has 8 divisors (see below), whose sum is σ = 1359643779984. Its totient is φ = 1326982567680.

The previous prime is 1343311413097. The next prime is 1343311413149. The reversal of 1343311413131 is 1313141133431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1343311413131 - 2¹⁴ = 1343311396747 is a prime.

It is a super-2 number, since 2×1343311413131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343311413094 and 1343311413103.

It is not an unprimeable number, because it can be changed into a prime (1343311413151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108686 + ... + 1642691.

It is an arithmetic number, because the mean of its divisors is an integer number (169955472498).

Almost surely, 2^{1343311413131} is an apocalyptic number.

1343311413131 is a deficient number, since it is larger than the sum of its proper divisors (16332366853).

1343311413131 is an equidigital number, since it uses as much as digits as its factorization.

1343311413131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1760701.

The product of its digits is 3888, while the sum is 29.

Adding to 1343311413131 its reverse (1313141133431), we get a palindrome (2656452546562).

The spelling of 1343311413131 in words is "one trillion, three hundred forty-three billion, three hundred eleven million, four hundred thirteen thousand, one hundred thirty-one".