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13433202011 = 103439297083
BaseRepresentation
bin11001000001010111…
…00110010101011011
31021200011221100220102
430200223212111123
5210002344431021
610100544050015
7653613222155
oct144053462533
937604840812
1013433202011
115773768549
12272a90390b
131361069858
149160d3ad5
155394c300b
hex320ae655b

13433202011 has 8 divisors (see below), whose sum is σ = 13594563840. Its totient is φ = 13272435432.

The previous prime is 13433201923. The next prime is 13433202031. The reversal of 13433202011 is 11020233431.

13433202011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13433202011 - 210 = 13433200987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13433202031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103325 + ... + 193758.

It is an arithmetic number, because the mean of its divisors is an integer number (1699320480).

Almost surely, 213433202011 is an apocalyptic number.

13433202011 is a deficient number, since it is larger than the sum of its proper divisors (161361829).

13433202011 is a wasteful number, since it uses less digits than its factorization.

13433202011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297625.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13433202011 its reverse (11020233431), we get a palindrome (24453435442).

The spelling of 13433202011 in words is "thirteen billion, four hundred thirty-three million, two hundred two thousand, eleven".

Divisors: 1 103 439 45217 297083 30599549 130419437 13433202011