1343340121 has 4 divisors (see below), whose sum is σ = 1343856052. Its totient is φ = 1342824192.

The previous prime is 1343340079. The next prime is 1343340133. The reversal of 1343340121 is 1210433431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1028100096 + 315240025 = 32064^2 + 17755^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343340121 - 2¹³ = 1343331929 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343340092 and 1343340101.

It is not an unprimeable number, because it can be changed into a prime (1343340161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254040 + ... + 259273.

It is an arithmetic number, because the mean of its divisors is an integer number (335964013).

Almost surely, 2^1343340121 is an apocalyptic number.

It is an amenable number.

1343340121 is a deficient number, since it is larger than the sum of its proper divisors (515931).

1343340121 is an equidigital number, since it uses as much as digits as its factorization.

1343340121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 515930.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 1343340121 is about 36651.6046169878. The cubic root of 1343340121 is about 1103.3890302587.

Adding to 1343340121 its reverse (1210433431), we get a palindrome (2553773552).

The spelling of 1343340121 in words is "one billion, three hundred forty-three million, three hundred forty thousand, one hundred twenty-one".