Base | Representation |
---|---|
bin | 111110100011011110… |
… | …0111001001010000011 |
3 | 110211201222210020121100 |
4 | 1331012330321022003 |
5 | 4200104043312201 |
6 | 141413511225443 |
7 | 12463634112042 |
oct | 1750674711203 |
9 | 424658706540 |
10 | 134334354051 |
11 | 51a75271517 |
12 | 22050378283 |
13 | c88ab61a81 |
14 | 6704db6559 |
15 | 3763631886 |
hex | 1f46f39283 |
134334354051 has 6 divisors (see below), whose sum is σ = 194038511420. Its totient is φ = 89556236028.
The previous prime is 134334354031. The next prime is 134334354067. The reversal of 134334354051 is 150453433431.
134334354051 is a `hidden beast` number, since 1 + 34 + 3 + 34 + 3 + 540 + 51 = 666.
It is not a de Polignac number, because 134334354051 - 29 = 134334353539 is a prime.
It is a super-2 number, since 2×1343343540512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134334353997 and 134334354015.
It is not an unprimeable number, because it can be changed into a prime (134334354031) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7463019661 + ... + 7463019678.
Almost surely, 2134334354051 is an apocalyptic number.
134334354051 is a deficient number, since it is larger than the sum of its proper divisors (59704157369).
134334354051 is a wasteful number, since it uses less digits than its factorization.
134334354051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14926039345 (or 14926039342 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 36.
Adding to 134334354051 its reverse (150453433431), we get a palindrome (284787787482).
The spelling of 134334354051 in words is "one hundred thirty-four billion, three hundred thirty-four million, three hundred fifty-four thousand, fifty-one".
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