Base | Representation |
---|---|
bin | 1100001101111011011110… |
… | …0100000100110011110001 |
3 | 1202120020001200212221212120 |
4 | 3003132313210010303301 |
5 | 3230043142230001001 |
6 | 44323123243544453 |
7 | 2554351140402120 |
oct | 303366744046361 |
9 | 52506050787776 |
10 | 13433442422001 |
11 | 430a100046788 |
12 | 160b5a882b129 |
13 | 7659ca918734 |
14 | 3462798c3ab7 |
15 | 18467bee1236 |
hex | c37b7904cf1 |
13433442422001 has 8 divisors (see below), whose sum is σ = 20470007500224. Its totient is φ = 7676252812560.
The previous prime is 13433442421979. The next prime is 13433442422063. The reversal of 13433442422001 is 10022424433431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13433442422001 - 218 = 13433442159857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13433442422401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319843867170 + ... + 319843867211.
It is an arithmetic number, because the mean of its divisors is an integer number (2558750937528).
Almost surely, 213433442422001 is an apocalyptic number.
It is an amenable number.
13433442422001 is a deficient number, since it is larger than the sum of its proper divisors (7036565078223).
13433442422001 is an equidigital number, since it uses as much as digits as its factorization.
13433442422001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 639687734391.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13433442422001 its reverse (10022424433431), we get a palindrome (23455866855432).
The spelling of 13433442422001 in words is "thirteen trillion, four hundred thirty-three billion, four hundred forty-two million, four hundred twenty-two thousand, one".
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