Base | Representation |
---|---|
bin | 11110100010111010010011… |
… | …011101010010000111001011 |
3 | 122121122211012201011100200222 |
4 | 132202322103131102013023 |
5 | 120102013231004331103 |
6 | 1153415053353020255 |
7 | 40203530600441513 |
oct | 3642722335220713 |
9 | 577584181140628 |
10 | 134340461011403 |
11 | 39894518aa0899 |
12 | 130980b86b468b |
13 | 59c633591578a |
14 | 2526182134843 |
15 | 107e784e10638 |
hex | 7a2e937521cb |
134340461011403 has 4 divisors (see below), whose sum is σ = 134380598589000. Its totient is φ = 134300323433808.
The previous prime is 134340461011303. The next prime is 134340461011409. The reversal of 134340461011403 is 304110164043431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134340461011403 - 224 = 134340444234187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134340461011409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20068783778 + ... + 20068790471.
It is an arithmetic number, because the mean of its divisors is an integer number (33595149647250).
Almost surely, 2134340461011403 is an apocalyptic number.
134340461011403 is a deficient number, since it is larger than the sum of its proper divisors (40137577597).
134340461011403 is an equidigital number, since it uses as much as digits as its factorization.
134340461011403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40137577596.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 134340461011403 in words is "one hundred thirty-four trillion, three hundred forty billion, four hundred sixty-one million, eleven thousand, four hundred three".
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