134342410411 has 4 divisors (see below), whose sum is σ = 146555356824. Its totient is φ = 122129464000.

The previous prime is 134342410399. The next prime is 134342410453. The reversal of 134342410411 is 114014243431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 114014243431 = 11 ⋅10364931221.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134342410411 is a prime.

It is a super-2 number, since 2×134342410411² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134342410411.

It is not an unprimeable number, because it can be changed into a prime (134342414411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6106473190 + ... + 6106473211.

It is an arithmetic number, because the mean of its divisors is an integer number (36638839206).

Almost surely, 2^134342410411 is an apocalyptic number.

134342410411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

134342410411 is a deficient number, since it is larger than the sum of its proper divisors (12212946413).

134342410411 is a wasteful number, since it uses less digits than its factorization.

134342410411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12212946412.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 134342410411 its reverse (114014243431), we get a palindrome (248356653842).

It can be divided in two parts, 1343424 and 10411, that added together give a triangular number (1353835 = T₁₆₄₅).

The spelling of 134342410411 in words is "one hundred thirty-four billion, three hundred forty-two million, four hundred ten thousand, four hundred eleven".