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134343100121 = 314333648391
BaseRepresentation
bin111110100011101111…
…0010000011011011001
3110211202121020120221212
41331013132100123121
54200113313200441
6141414422512505
712464101336556
oct1750736203331
9424677216855
10134343100121
1151a7a1a557a
1222053295735
13c88c904969
146706211a2d
1537642aceeb
hex1f477906d9

134343100121 has 4 divisors (see below), whose sum is σ = 138676748544. Its totient is φ = 130009451700.

The previous prime is 134343100103. The next prime is 134343100141. The reversal of 134343100121 is 121001343431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121001343431 = 683177161557.

It is a cyclic number.

It is not a de Polignac number, because 134343100121 - 222 = 134338905817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134343100141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166824165 + ... + 2166824226.

It is an arithmetic number, because the mean of its divisors is an integer number (34669187136).

Almost surely, 2134343100121 is an apocalyptic number.

It is an amenable number.

134343100121 is a deficient number, since it is larger than the sum of its proper divisors (4333648423).

134343100121 is an equidigital number, since it uses as much as digits as its factorization.

134343100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4333648422.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 134343100121 its reverse (121001343431), we get a palindrome (255344443552).

The spelling of 134343100121 in words is "one hundred thirty-four billion, three hundred forty-three million, one hundred thousand, one hundred twenty-one".

Divisors: 1 31 4333648391 134343100121