Base | Representation |
---|---|
bin | 111110100011110001… |
… | …1010000110011110011 |
3 | 110211202200201021001220 |
4 | 1331013203100303303 |
5 | 4200114132144103 |
6 | 141414511000123 |
7 | 12464115443505 |
oct | 1750743206363 |
9 | 424680637056 |
10 | 134344412403 |
11 | 51a7aa11503 |
12 | 22053809043 |
13 | c88cc74066 |
14 | 6706473d75 |
15 | 376446bc53 |
hex | 1f478d0cf3 |
134344412403 has 4 divisors (see below), whose sum is σ = 179125883208. Its totient is φ = 89562941600.
The previous prime is 134344412341. The next prime is 134344412491. The reversal of 134344412403 is 304214443431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304214443431 = 3 ⋅101404814477.
It is a cyclic number.
It is not a de Polignac number, because 134344412403 - 26 = 134344412339 is a prime.
It is a super-2 number, since 2×1343444124032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (134344412903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22390735398 + ... + 22390735403.
It is an arithmetic number, because the mean of its divisors is an integer number (44781470802).
Almost surely, 2134344412403 is an apocalyptic number.
134344412403 is a deficient number, since it is larger than the sum of its proper divisors (44781470805).
134344412403 is an equidigital number, since it uses as much as digits as its factorization.
134344412403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44781470804.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 134344412403 its reverse (304214443431), we get a palindrome (438558855834).
The spelling of 134344412403 in words is "one hundred thirty-four billion, three hundred forty-four million, four hundred twelve thousand, four hundred three".
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