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134344412403 = 344781470801
BaseRepresentation
bin111110100011110001…
…1010000110011110011
3110211202200201021001220
41331013203100303303
54200114132144103
6141414511000123
712464115443505
oct1750743206363
9424680637056
10134344412403
1151a7aa11503
1222053809043
13c88cc74066
146706473d75
15376446bc53
hex1f478d0cf3

134344412403 has 4 divisors (see below), whose sum is σ = 179125883208. Its totient is φ = 89562941600.

The previous prime is 134344412341. The next prime is 134344412491. The reversal of 134344412403 is 304214443431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304214443431 = 3101404814477.

It is a cyclic number.

It is not a de Polignac number, because 134344412403 - 26 = 134344412339 is a prime.

It is a super-2 number, since 2×1343444124032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (134344412903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22390735398 + ... + 22390735403.

It is an arithmetic number, because the mean of its divisors is an integer number (44781470802).

Almost surely, 2134344412403 is an apocalyptic number.

134344412403 is a deficient number, since it is larger than the sum of its proper divisors (44781470805).

134344412403 is an equidigital number, since it uses as much as digits as its factorization.

134344412403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44781470804.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 134344412403 its reverse (304214443431), we get a palindrome (438558855834).

The spelling of 134344412403 in words is "one hundred thirty-four billion, three hundred forty-four million, four hundred twelve thousand, four hundred three".

Divisors: 1 3 44781470801 134344412403