Base | Representation |
---|---|
bin | 10011100011010111010… |
… | …001011011011111010001 |
3 | 11202110011200110200010121 |
4 | 103203113101123133101 |
5 | 134003234203414313 |
6 | 2505132123430241 |
7 | 166034455011511 |
oct | 23432721333721 |
9 | 4673150420117 |
10 | 1343641466833 |
11 | 478920641156 |
12 | 1984a6985381 |
13 | 999217181b3 |
14 | 4906561b841 |
15 | 24e4046028d |
hex | 138d745b7d1 |
1343641466833 has 4 divisors (see below), whose sum is σ = 1343653300080. Its totient is φ = 1343629633588.
The previous prime is 1343641466801. The next prime is 1343641466941. The reversal of 1343641466833 is 3386641463431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1343641466833 - 25 = 1343641466801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1343641466633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5744635 + ... + 5973952.
It is an arithmetic number, because the mean of its divisors is an integer number (335913325020).
Almost surely, 21343641466833 is an apocalyptic number.
It is an amenable number.
1343641466833 is a deficient number, since it is larger than the sum of its proper divisors (11833247).
1343641466833 is a wasteful number, since it uses less digits than its factorization.
1343641466833 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11833246.
The product of its digits is 8957952, while the sum is 52.
The spelling of 1343641466833 in words is "one trillion, three hundred forty-three billion, six hundred forty-one million, four hundred sixty-six thousand, eight hundred thirty-three".
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