Base | Representation |
---|---|
bin | 11001000010001100… |
… | …11010001010100011 |
3 | 1021200200011102120012 |
4 | 30201012122022203 |
5 | 210011144330201 |
6 | 10101354435135 |
7 | 654030033113 |
oct | 144106321243 |
9 | 37620142505 |
10 | 13440230051 |
11 | 5777728846 |
12 | 2731132aab |
13 | 136265a761 |
14 | 917003043 |
15 | 539e105bb |
hex | 32119a2a3 |
13440230051 has 8 divisors (see below), whose sum is σ = 14148691200. Its totient is φ = 12731877000.
The previous prime is 13440230047. The next prime is 13440230071. The reversal of 13440230051 is 15003204431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13440230051 - 22 = 13440230047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13440229999 and 13440230026.
It is not an unprimeable number, because it can be changed into a prime (13440230071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 407426 + ... + 439176.
It is an arithmetic number, because the mean of its divisors is an integer number (1768586400).
Almost surely, 213440230051 is an apocalyptic number.
13440230051 is a deficient number, since it is larger than the sum of its proper divisors (708461149).
13440230051 is a wasteful number, since it uses less digits than its factorization.
13440230051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54049.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 13440230051 its reverse (15003204431), we get a palindrome (28443434482).
The spelling of 13440230051 in words is "thirteen billion, four hundred forty million, two hundred thirty thousand, fifty-one".
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