13440301241 has 4 divisors (see below), whose sum is σ = 13491405312. Its totient is φ = 13389197172.

The previous prime is 13440301223. The next prime is 13440301253. The reversal of 13440301241 is 14210304431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14210304431 = 41 ⋅346592791.

It is a cyclic number.

It is not a de Polignac number, because 13440301241 - 2¹⁴ = 13440284857 is a prime.

It is a super-2 number, since 2×13440301241² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13440301271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25551641 + ... + 25552166.

It is an arithmetic number, because the mean of its divisors is an integer number (3372851328).

Almost surely, 2^13440301241 is an apocalyptic number.

It is an amenable number.

13440301241 is a deficient number, since it is larger than the sum of its proper divisors (51104071).

13440301241 is an equidigital number, since it uses as much as digits as its factorization.

13440301241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51104070.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13440301241 its reverse (14210304431), we get a palindrome (27650605672).

The spelling of 13440301241 in words is "thirteen billion, four hundred forty million, three hundred one thousand, two hundred forty-one".