134406514603 has 4 divisors (see below), whose sum is σ = 134421729520. Its totient is φ = 134391299688.

The previous prime is 134406514601. The next prime is 134406514607. The reversal of 134406514603 is 306415604431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 306415604431 = 261451 ⋅1171981.

It is a cyclic number.

It is not a de Polignac number, because 134406514603 - 2¹ = 134406514601 is a prime.

It is a super-2 number, since 2×134406514603² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134406514601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7594200 + ... + 7611877.

It is an arithmetic number, because the mean of its divisors is an integer number (33605432380).

Almost surely, 2^134406514603 is an apocalyptic number.

134406514603 is a deficient number, since it is larger than the sum of its proper divisors (15214917).

134406514603 is an equidigital number, since it uses as much as digits as its factorization.

134406514603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15214916.

The product of its (nonzero) digits is 103680, while the sum is 37.

The spelling of 134406514603 in words is "one hundred thirty-four billion, four hundred six million, five hundred fourteen thousand, six hundred three".