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1344097491483 = 31572853710173
BaseRepresentation
bin10011100011110010011…
…101000001101000011011
311202111100110120010100110
4103203302131001220123
5134010202424211413
62505245253535403
7166051663112445
oct23436235015033
94674313503313
101344097491483
11479034aa222a
121985b3644563
1399995044176
14490aa007495
1524e6a4dd8c3
hex138f2741a1b

1344097491483 has 8 divisors (see below), whose sum is σ = 1803544829968. Its totient is φ = 890357573664.

The previous prime is 1344097491479. The next prime is 1344097491511. The reversal of 1344097491483 is 3841947904431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1344097491483 - 22 = 1344097491479 is a prime.

It is a super-2 number, since 2×13440974914832 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344097491403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1426854616 + ... + 1426855557.

It is an arithmetic number, because the mean of its divisors is an integer number (225443103746).

Almost surely, 21344097491483 is an apocalyptic number.

1344097491483 is a deficient number, since it is larger than the sum of its proper divisors (459447338485).

1344097491483 is a wasteful number, since it uses less digits than its factorization.

1344097491483 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2853710333.

The product of its (nonzero) digits is 10450944, while the sum is 57.

The spelling of 1344097491483 in words is "one trillion, three hundred forty-four billion, ninety-seven million, four hundred ninety-one thousand, four hundred eighty-three".

Divisors: 1 3 157 471 2853710173 8561130519 448032497161 1344097491483