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134411131442323 = 559423324026731
BaseRepresentation
bin11110100011111100000111…
…101111100101010010010011
3122121220120121212001012220101
4132203330013233211102103
5120104142444122123243
61153511342113353231
740211612065260331
oct3643740757452223
9577816555035811
10134411131442323
11399114936765aa
12130a993bb68817
1359ccbb8c186c8
142529767bc8b51
15108151e30254d
hex7a3f07be5493

134411131442323 has 4 divisors (see below), whose sum is σ = 134411161063288. Its totient is φ = 134411101821360.

The previous prime is 134411131442303. The next prime is 134411131442333. The reversal of 134411131442323 is 323244131114431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134411131442323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134411131442303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6419133 + ... + 17607598.

It is an arithmetic number, because the mean of its divisors is an integer number (33602790265822).

Almost surely, 2134411131442323 is an apocalyptic number.

134411131442323 is a deficient number, since it is larger than the sum of its proper divisors (29620965).

134411131442323 is an equidigital number, since it uses as much as digits as its factorization.

134411131442323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29620964.

The product of its digits is 82944, while the sum is 37.

Adding to 134411131442323 its reverse (323244131114431), we get a palindrome (457655262556754).

The spelling of 134411131442323 in words is "one hundred thirty-four trillion, four hundred eleven billion, one hundred thirty-one million, four hundred forty-two thousand, three hundred twenty-three".

Divisors: 1 5594233 24026731 134411131442323