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13441200222011 = 41593231834629
BaseRepresentation
bin1100001110011000010111…
…1101101110111100111011
31202120222002100120000211212
43003212011331232330323
53230210034224101021
644330445132313335
72555044320534632
oct303460575567473
952528070500755
1013441200222011
114312421128751
121610bb291284b
13766665c1a543
143467b3d42519
151849830e885b
hexc3985f6ef3b

13441200222011 has 4 divisors (see below), whose sum is σ = 13444432060800. Its totient is φ = 13437968383224.

The previous prime is 13441200222001. The next prime is 13441200222061. The reversal of 13441200222011 is 11022200214431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13441200222011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13441200222001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1615913156 + ... + 1615921473.

It is an arithmetic number, because the mean of its divisors is an integer number (3361108015200).

Almost surely, 213441200222011 is an apocalyptic number.

13441200222011 is a deficient number, since it is larger than the sum of its proper divisors (3231838789).

13441200222011 is an equidigital number, since it uses as much as digits as its factorization.

13441200222011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3231838788.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13441200222011 its reverse (11022200214431), we get a palindrome (24463400436442).

The spelling of 13441200222011 in words is "thirteen trillion, four hundred forty-one billion, two hundred million, two hundred twenty-two thousand, eleven".

Divisors: 1 4159 3231834629 13441200222011