13441212041 has 4 divisors (see below), whose sum is σ = 13441584000. Its totient is φ = 13440840084.

The previous prime is 13441212017. The next prime is 13441212077. The reversal of 13441212041 is 14021214431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14021214431 = 7 ⋅2003030633.

It is a cyclic number.

It is not a de Polignac number, because 13441212041 - 2³⁰ = 12367470217 is a prime.

It is a super-2 number, since 2×13441212041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13441211998 and 13441212016.

It is not an unprimeable number, because it can be changed into a prime (13441212241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125141 + ... + 206258.

It is an arithmetic number, because the mean of its divisors is an integer number (3360396000).

Almost surely, 2^13441212041 is an apocalyptic number.

It is an amenable number.

13441212041 is a deficient number, since it is larger than the sum of its proper divisors (371959).

13441212041 is an equidigital number, since it uses as much as digits as its factorization.

13441212041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371958.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13441212041 its reverse (14021214431), we get a palindrome (27462426472).

The spelling of 13441212041 in words is "thirteen billion, four hundred forty-one million, two hundred twelve thousand, forty-one".