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13441325221003 = 44330341591921
BaseRepresentation
bin1100001110011000110101…
…1010100100010010001011
31202120222102001202122020011
43003212031122210102023
53230210313224033003
644330505355412351
72555050366156321
oct303461532442213
952528361678204
1013441325221003
1143124857442a9
1216110287540b7
13766685aa4944
143467c679dd11
1518498e08a46d
hexc398d6a448b

13441325221003 has 4 divisors (see below), whose sum is σ = 13471666813368. Its totient is φ = 13410983628640.

The previous prime is 13441325221001. The next prime is 13441325221061. The reversal of 13441325221003 is 30012252314431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13441325221003 - 21 = 13441325221001 is a prime.

It is a super-3 number, since 3×134413252210033 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13441325221001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15170795518 + ... + 15170796403.

It is an arithmetic number, because the mean of its divisors is an integer number (3367916703342).

Almost surely, 213441325221003 is an apocalyptic number.

13441325221003 is a deficient number, since it is larger than the sum of its proper divisors (30341592365).

13441325221003 is an equidigital number, since it uses as much as digits as its factorization.

13441325221003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30341592364.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13441325221003 its reverse (30012252314431), we get a palindrome (43453577535434).

The spelling of 13441325221003 in words is "thirteen trillion, four hundred forty-one billion, three hundred twenty-five million, two hundred twenty-one thousand, three".

Divisors: 1 443 30341591921 13441325221003