1344140013011 has 4 divisors (see below), whose sum is σ = 1344142482024. Its totient is φ = 1344137544000.

The previous prime is 1344140012989. The next prime is 1344140013109. The reversal of 1344140013011 is 1103100414431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1344140013011 - 2¹⁸ = 1344139750867 is a prime.

It is a super-2 number, since 2×1344140013011² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344140013511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18905 + ... + 1639706.

It is an arithmetic number, because the mean of its divisors is an integer number (336035620506).

Almost surely, 2^{1344140013011} is an apocalyptic number.

1344140013011 is a deficient number, since it is larger than the sum of its proper divisors (2469013).

1344140013011 is an equidigital number, since it uses as much as digits as its factorization.

1344140013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2469012.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1344140013011 its reverse (1103100414431), we get a palindrome (2447240427442).

The spelling of 1344140013011 in words is "one trillion, three hundred forty-four billion, one hundred forty million, thirteen thousand, eleven".