Base | Representation |
---|---|
bin | 11001000010011011… |
… | …00111101011110001 |
3 | 1021200210201110200100 |
4 | 30201031213223301 |
5 | 210012140323213 |
6 | 10101503143013 |
7 | 654052065330 |
oct | 144115475361 |
9 | 37623643610 |
10 | 13442120433 |
11 | 57787aa045 |
12 | 27318a4a69 |
13 | 1362b70021 |
14 | 917375d17 |
15 | 53a185773 |
hex | 321367af1 |
13442120433 has 12 divisors (see below), whose sum is σ = 22190167168. Its totient is φ = 7681211640.
The previous prime is 13442120411. The next prime is 13442120449. The reversal of 13442120433 is 33402124431.
13442120433 is a `hidden beast` number, since 1 + 3 + 4 + 421 + 204 + 33 = 666.
It is not a de Polignac number, because 13442120433 - 29 = 13442119921 is a prime.
It is a super-2 number, since 2×134421204332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13442120397 and 13442120406.
It is not an unprimeable number, because it can be changed into a prime (13442120453) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 106683433 + ... + 106683558.
Almost surely, 213442120433 is an apocalyptic number.
It is an amenable number.
13442120433 is a deficient number, since it is larger than the sum of its proper divisors (8748046735).
13442120433 is a wasteful number, since it uses less digits than its factorization.
13442120433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213367004 (or 213367001 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 13442120433 its reverse (33402124431), we get a palindrome (46844244864).
The spelling of 13442120433 in words is "thirteen billion, four hundred forty-two million, one hundred twenty thousand, four hundred thirty-three".
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