13442440033 has 4 divisors (see below), whose sum is σ = 14664480048. Its totient is φ = 12220400020.

The previous prime is 13442440027. The next prime is 13442440057. The reversal of 13442440033 is 33004424431.

13442440033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33004424431 = 11 ⋅3000402221.

It is a cyclic number.

It is not a de Polignac number, because 13442440033 - 2²⁵ = 13408885601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13442439983 and 13442440010.

It is not an unprimeable number, because it can be changed into a prime (13442440013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611019991 + ... + 611020012.

It is an arithmetic number, because the mean of its divisors is an integer number (3666120012).

Almost surely, 2^13442440033 is an apocalyptic number.

It is an amenable number.

13442440033 is a deficient number, since it is larger than the sum of its proper divisors (1222040015).

13442440033 is a wasteful number, since it uses less digits than its factorization.

13442440033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1222040014.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 13442440033 its reverse (33004424431), we get a palindrome (46446864464).

The spelling of 13442440033 in words is "thirteen billion, four hundred forty-two million, four hundred forty thousand, thirty-three".