13442520034131 has 4 divisors (see below), whose sum is σ = 17923360045512. Its totient is φ = 8961680022752.

The previous prime is 13442520034129. The next prime is 13442520034133. The reversal of 13442520034131 is 13143002524431.

13442520034131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13442520034129) and next prime (13442520034133).

It is a cyclic number.

It is not a de Polignac number, because 13442520034131 - 2¹ = 13442520034129 is a prime.

It is a super-2 number, since 2×13442520034131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13442520034092 and 13442520034101.

It is not an unprimeable number, because it can be changed into a prime (13442520034133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240420005686 + ... + 2240420005691.

It is an arithmetic number, because the mean of its divisors is an integer number (4480840011378).

Almost surely, 2^{13442520034131} is an apocalyptic number.

13442520034131 is a deficient number, since it is larger than the sum of its proper divisors (4480840011381).

13442520034131 is an equidigital number, since it uses as much as digits as its factorization.

13442520034131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4480840011380.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13442520034131 its reverse (13143002524431), we get a palindrome (26585522558562).

The spelling of 13442520034131 in words is "thirteen trillion, four hundred forty-two billion, five hundred twenty million, thirty-four thousand, one hundred thirty-one".