13442520254353 has 4 divisors (see below), whose sum is σ = 13445415481968. Its totient is φ = 13439625026740.

The previous prime is 13442520254297. The next prime is 13442520254389. The reversal of 13442520254353 is 35345202524431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13442520254353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13442520251353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1447606843 + ... + 1447616128.

It is an arithmetic number, because the mean of its divisors is an integer number (3361353870492).

Almost surely, 2^{13442520254353} is an apocalyptic number.

It is an amenable number.

13442520254353 is a deficient number, since it is larger than the sum of its proper divisors (2895227615).

13442520254353 is an equidigital number, since it uses as much as digits as its factorization.

13442520254353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2895227614.

The product of its (nonzero) digits is 1728000, while the sum is 43.

Adding to 13442520254353 its reverse (35345202524431), we get a palindrome (48787722778784).

The spelling of 13442520254353 in words is "thirteen trillion, four hundred forty-two billion, five hundred twenty million, two hundred fifty-four thousand, three hundred fifty-three".