Base | Representation |
---|---|
bin | 11001000010100001… |
… | …11110101100101011 |
3 | 1021200212101012202210 |
4 | 30201100332230223 |
5 | 210012402014011 |
6 | 10101534100203 |
7 | 654062424060 |
oct | 144120765453 |
9 | 37625335683 |
10 | 13443001131 |
11 | 577925079a |
12 | 273204a663 |
13 | 13630bab51 |
14 | 917524c67 |
15 | 53a2ab6a6 |
hex | 32143eb2b |
13443001131 has 16 divisors (see below), whose sum is σ = 20487908864. Its totient is φ = 7680464064.
The previous prime is 13443001097. The next prime is 13443001133. The reversal of 13443001131 is 13110034431.
13443001131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13443001131 - 210 = 13443000107 is a prime.
It is a super-2 number, since 2×134430011312 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13443001098 and 13443001107.
It is not an unprimeable number, because it can be changed into a prime (13443001133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88770 + ... + 186456.
It is an arithmetic number, because the mean of its divisors is an integer number (1280494304).
Almost surely, 213443001131 is an apocalyptic number.
13443001131 is a deficient number, since it is larger than the sum of its proper divisors (7044907733).
13443001131 is an equidigital number, since it uses as much as digits as its factorization.
13443001131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104250.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13443001131 its reverse (13110034431), we get a palindrome (26553035562).
It can be divided in two parts, 1344300 and 1131, that added together give a palindrome (1345431).
The spelling of 13443001131 in words is "thirteen billion, four hundred forty-three million, one thousand, one hundred thirty-one".
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