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1344300241441 = 3547378996403
BaseRepresentation
bin10011100011111110100…
…010011101001000100001
311202111212121001220000011
4103203332202131020201
5134011111330211231
62505321335324521
7166060004342263
oct23437642351041
94674777056004
101344300241441
11479129493283
1219864b520741
13999c8052061
14490c8d03b33
1524e7d1dc9b1
hex138fe89d221

1344300241441 has 4 divisors (see below), whose sum is σ = 1344679241392. Its totient is φ = 1343921241492.

The previous prime is 1344300241429. The next prime is 1344300241451. The reversal of 1344300241441 is 1441420034431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344300241441 - 219 = 1344299717153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344300241421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189494655 + ... + 189501748.

It is an arithmetic number, because the mean of its divisors is an integer number (336169810348).

Almost surely, 21344300241441 is an apocalyptic number.

It is an amenable number.

1344300241441 is a deficient number, since it is larger than the sum of its proper divisors (378999951).

1344300241441 is an equidigital number, since it uses as much as digits as its factorization.

1344300241441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 378999950.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1344300241441 its reverse (1441420034431), we get a palindrome (2785720275872).

The spelling of 1344300241441 in words is "one trillion, three hundred forty-four billion, three hundred million, two hundred forty-one thousand, four hundred forty-one".

Divisors: 1 3547 378996403 1344300241441