Search a number
-
+
1344311314123 = 8915104621507
BaseRepresentation
bin10011100011111111001…
…100101100011011001011
311202111220100220102212111
4103203333030230123023
5134011122144022443
62505322412523151
7166060200430201
oct23437714543313
94674810812774
101344311314123
11479134766358
121986531804b7
13999ca42ac3b
14490ca587071
1524e7e17869d
hex138ff32c6cb

1344311314123 has 4 divisors (see below), whose sum is σ = 1359415935720. Its totient is φ = 1329206692528.

The previous prime is 1344311314109. The next prime is 1344311314139. The reversal of 1344311314123 is 3214131134431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344311314123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344311314523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7552310665 + ... + 7552310842.

It is an arithmetic number, because the mean of its divisors is an integer number (339853983930).

Almost surely, 21344311314123 is an apocalyptic number.

1344311314123 is a deficient number, since it is larger than the sum of its proper divisors (15104621597).

1344311314123 is an equidigital number, since it uses as much as digits as its factorization.

1344311314123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15104621596.

The product of its digits is 10368, while the sum is 31.

Adding to 1344311314123 its reverse (3214131134431), we get a palindrome (4558442448554).

The spelling of 1344311314123 in words is "one trillion, three hundred forty-four billion, three hundred eleven million, three hundred fourteen thousand, one hundred twenty-three".

Divisors: 1 89 15104621507 1344311314123