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134431400001 = 344810466667
BaseRepresentation
bin111110100110010111…
…1000110000001000001
3110211222202101200121210
41331030233012001001
54200303414300001
6141431255240333
712466223021613
oct1751457060101
9424882350553
10134431400001
1152015025588
12220789790a9
13c8a4cacb02
146713c38db3
15376be00dd6
hex1f4cbc6041

134431400001 has 4 divisors (see below), whose sum is σ = 179241866672. Its totient is φ = 89620933332.

The previous prime is 134431399957. The next prime is 134431400039. The reversal of 134431400001 is 100004134431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 134431400001 - 29 = 134431399489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134431400101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22405233331 + ... + 22405233336.

It is an arithmetic number, because the mean of its divisors is an integer number (44810466668).

Almost surely, 2134431400001 is an apocalyptic number.

It is an amenable number.

134431400001 is a deficient number, since it is larger than the sum of its proper divisors (44810466671).

134431400001 is an equidigital number, since it uses as much as digits as its factorization.

134431400001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44810466670.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 134431400001 its reverse (100004134431), we get a palindrome (234435534432).

The spelling of 134431400001 in words is "one hundred thirty-four billion, four hundred thirty-one million, four hundred thousand, one".

Divisors: 1 3 44810466667 134431400001