Search a number
-
+
1344314334201 = 3448104778067
BaseRepresentation
bin10011100011111111011…
…000001101101111111001
311202111220120120212122020
4103203333120031233321
5134011123432143301
62505323001345053
7166060235206116
oct23437730155771
94674816525566
101344314334201
11479136439393
12198654198189
13999cac47777
14490cab3190d
1524e7e573436
hex138ff60dbf9

1344314334201 has 4 divisors (see below), whose sum is σ = 1792419112272. Its totient is φ = 896209556132.

The previous prime is 1344314334173. The next prime is 1344314334239. The reversal of 1344314334201 is 1024334134431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344314334201 - 227 = 1344180116473 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1344314334001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224052389031 + ... + 224052389036.

It is an arithmetic number, because the mean of its divisors is an integer number (448104778068).

Almost surely, 21344314334201 is an apocalyptic number.

It is an amenable number.

1344314334201 is a deficient number, since it is larger than the sum of its proper divisors (448104778071).

1344314334201 is an equidigital number, since it uses as much as digits as its factorization.

1344314334201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448104778070.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1344314334201 its reverse (1024334134431), we get a palindrome (2368648468632).

The spelling of 1344314334201 in words is "one trillion, three hundred forty-four billion, three hundred fourteen million, three hundred thirty-four thousand, two hundred one".

Divisors: 1 3 448104778067 1344314334201