13443210113113 has 4 divisors (see below), whose sum is σ = 14665320123408. Its totient is φ = 12221100102820.

The previous prime is 13443210113111. The next prime is 13443210113173. The reversal of 13443210113113 is 31131101234431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13443210113113 - 2¹ = 13443210113111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13443210113111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611055005131 + ... + 611055005152.

It is an arithmetic number, because the mean of its divisors is an integer number (3666330030852).

Almost surely, 2^{13443210113113} is an apocalyptic number.

It is an amenable number.

13443210113113 is a deficient number, since it is larger than the sum of its proper divisors (1222110010295).

13443210113113 is a wasteful number, since it uses less digits than its factorization.

13443210113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1222110010294.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 13443210113113 its reverse (31131101234431), we get a palindrome (44574311347544).

The spelling of 13443210113113 in words is "thirteen trillion, four hundred forty-three billion, two hundred ten million, one hundred thirteen thousand, one hundred thirteen".