Base | Representation |
---|---|
bin | 1100001110100000010100… |
… | …1001100111001000111011 |
3 | 1202121011121001201022211011 |
4 | 3003220011021213020323 |
5 | 3230223422003322141 |
6 | 44331440555414351 |
7 | 2555151230650645 |
oct | 303500511471073 |
9 | 52534531638734 |
10 | 13443334042171 |
11 | 4313316666390 |
12 | 16114a94543b7 |
13 | 76691601a117 |
14 | 3469374b3895 |
15 | 184a5a5e1881 |
hex | c3a0526723b |
13443334042171 has 8 divisors (see below), whose sum is σ = 14672082302064. Its totient is φ = 12215690279520.
The previous prime is 13443334042153. The next prime is 13443334042217. The reversal of 13443334042171 is 17124043334431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13443334042171 - 29 = 13443334041659 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13443334042471) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 276098856 + ... + 276147541.
It is an arithmetic number, because the mean of its divisors is an integer number (1834010287758).
Almost surely, 213443334042171 is an apocalyptic number.
13443334042171 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13443334042171 is a deficient number, since it is larger than the sum of its proper divisors (1228748259893).
13443334042171 is a wasteful number, since it uses less digits than its factorization.
13443334042171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 552248621.
The product of its (nonzero) digits is 290304, while the sum is 40.
The spelling of 13443334042171 in words is "thirteen trillion, four hundred forty-three billion, three hundred thirty-four million, forty-two thousand, one hundred seventy-one".
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