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134433544451 = 510126354351
BaseRepresentation
bin111110100110011011…
…1010001100100000011
3110211222220102122020212
41331030313101210003
54200304441410301
6141431413224335
712466250162633
oct1751467214403
9424886378225
10134433544451
115201625a758
12220796320ab
13c8a5580c0b
1467142366c3
15376c1c64bb
hex1f4cdd1903

134433544451 has 4 divisors (see below), whose sum is σ = 134459903904. Its totient is φ = 134407185000.

The previous prime is 134433544439. The next prime is 134433544529. The reversal of 134433544451 is 154445334431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134433544451 - 218 = 134433282307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134433544399 and 134433544408.

It is not an unprimeable number, because it can be changed into a prime (134433544411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13172075 + ... + 13182276.

It is an arithmetic number, because the mean of its divisors is an integer number (33614975976).

Almost surely, 2134433544451 is an apocalyptic number.

134433544451 is a deficient number, since it is larger than the sum of its proper divisors (26359453).

134433544451 is an equidigital number, since it uses as much as digits as its factorization.

134433544451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26359452.

The product of its digits is 691200, while the sum is 41.

Adding to 134433544451 its reverse (154445334431), we get a palindrome (288878878882).

The spelling of 134433544451 in words is "one hundred thirty-four billion, four hundred thirty-three million, five hundred forty-four thousand, four hundred fifty-one".

Divisors: 1 5101 26354351 134433544451