13444030121 has 4 divisors (see below), whose sum is σ = 13877708544. Its totient is φ = 13010351700.

The previous prime is 13444030073. The next prime is 13444030207. The reversal of 13444030121 is 12103044431.

13444030121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12103044431 = 13523 ⋅894997.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13444030121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13444030921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216839165 + ... + 216839226.

It is an arithmetic number, because the mean of its divisors is an integer number (3469427136).

Almost surely, 2^13444030121 is an apocalyptic number.

It is an amenable number.

13444030121 is a deficient number, since it is larger than the sum of its proper divisors (433678423).

13444030121 is an equidigital number, since it uses as much as digits as its factorization.

13444030121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433678422.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13444030121 its reverse (12103044431), we get a palindrome (25547074552).

The spelling of 13444030121 in words is "thirteen billion, four hundred forty-four million, thirty thousand, one hundred twenty-one".