1344403100353 has 4 divisors (see below), whose sum is σ = 1402855409088. Its totient is φ = 1285950791620.

The previous prime is 1344403100317. The next prime is 1344403100377. The reversal of 1344403100353 is 3530013044431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344403100353 - 2⁹ = 1344403099841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344403100153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29226154333 + ... + 29226154378.

It is an arithmetic number, because the mean of its divisors is an integer number (350713852272).

Almost surely, 2^{1344403100353} is an apocalyptic number.

It is an amenable number.

1344403100353 is a deficient number, since it is larger than the sum of its proper divisors (58452308735).

1344403100353 is an equidigital number, since it uses as much as digits as its factorization.

1344403100353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58452308734.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 1344403100353 its reverse (3530013044431), we get a palindrome (4874416144784).

The spelling of 1344403100353 in words is "one trillion, three hundred forty-four billion, four hundred three million, one hundred thousand, three hundred fifty-three".