Base | Representation |
---|---|
bin | 1100001110100010111101… |
… | …1010001011111110101001 |
3 | 1202121020102110210122212222 |
4 | 3003220233122023332221 |
5 | 3230231400003433231 |
6 | 44332035203443425 |
7 | 2555204630156102 |
oct | 303505732137651 |
9 | 52536373718788 |
10 | 13444043030441 |
11 | 431364a894801 |
12 | 1611666986575 |
13 | 7669c9b856ca |
14 | 3469a370b3a9 |
15 | 184a9c98c27b |
hex | c3a2f68bfa9 |
13444043030441 has 4 divisors (see below), whose sum is σ = 13614220790400. Its totient is φ = 13273865270484.
The previous prime is 13444043030347. The next prime is 13444043030443. The reversal of 13444043030441 is 14403034044431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13444043030441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13444043030443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85088879861 + ... + 85088880018.
It is an arithmetic number, because the mean of its divisors is an integer number (3403555197600).
Almost surely, 213444043030441 is an apocalyptic number.
It is an amenable number.
13444043030441 is a deficient number, since it is larger than the sum of its proper divisors (170177759959).
13444043030441 is an equidigital number, since it uses as much as digits as its factorization.
13444043030441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170177759958.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 13444043030441 its reverse (14403034044431), we get a palindrome (27847077074872).
The spelling of 13444043030441 in words is "thirteen trillion, four hundred forty-four billion, forty-three million, thirty thousand, four hundred forty-one".
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