Base | Representation |
---|---|
bin | 11001000010101001… |
… | …11101010011100011 |
3 | 1021200221100012022200 |
4 | 30201110331103203 |
5 | 210013133402003 |
6 | 10102012304243 |
7 | 654104326365 |
oct | 144124752343 |
9 | 37627305280 |
10 | 13444044003 |
11 | 57798a3275 |
12 | 2732472083 |
13 | 1363394730 |
14 | 917716d35 |
15 | 53a4156a3 |
hex | 32153d4e3 |
13444044003 has 12 divisors (see below), whose sum is σ = 20912957520. Its totient is φ = 8273257776.
The previous prime is 13444043953. The next prime is 13444044011. The reversal of 13444044003 is 30044044431.
13444044003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13444044003 - 28 = 13444043747 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13444044403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57453063 + ... + 57453296.
It is an arithmetic number, because the mean of its divisors is an integer number (1742746460).
Almost surely, 213444044003 is an apocalyptic number.
13444044003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13444044003 is a deficient number, since it is larger than the sum of its proper divisors (7468913517).
13444044003 is a wasteful number, since it uses less digits than its factorization.
13444044003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114906378 (or 114906375 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 27.
Adding to 13444044003 its reverse (30044044431), we get a palindrome (43488088434).
The spelling of 13444044003 in words is "thirteen billion, four hundred forty-four million, forty-four thousand, three".
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