Base | Representation |
---|---|
bin | 10011100100000101010… |
… | …010001010011110000011 |
3 | 11202112011111000111201211 |
4 | 103210011102022132003 |
5 | 134011324313124303 |
6 | 2505340501110551 |
7 | 166062550305262 |
oct | 23440522123603 |
9 | 4675144014654 |
10 | 1344413411203 |
11 | 47918735a405 |
12 | 1986813b8457 |
13 | 99a15627105 |
14 | 490d9d625d9 |
15 | 24e880e466d |
hex | 1390548a783 |
1344413411203 has 8 divisors (see below), whose sum is σ = 1364729057280. Its totient is φ = 1324105111560.
The previous prime is 1344413411189. The next prime is 1344413411213. The reversal of 1344413411203 is 3021143144431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344413411203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1344413411213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1467283 + ... + 2200396.
It is an arithmetic number, because the mean of its divisors is an integer number (170591132160).
Almost surely, 21344413411203 is an apocalyptic number.
1344413411203 is a deficient number, since it is larger than the sum of its proper divisors (20315646077).
1344413411203 is an equidigital number, since it uses as much as digits as its factorization.
1344413411203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3673217.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1344413411203 its reverse (3021143144431), we get a palindrome (4365556555634).
The spelling of 1344413411203 in words is "one trillion, three hundred forty-four billion, four hundred thirteen million, four hundred eleven thousand, two hundred three".
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